![]() In its present form, the result equals array(1, G, 2, G, 3, G, 4, B, 5), because it assumes that the top-level array is childless until it finds otherwise. If I run it on $arrA, defined as array(1, 2, array(3, 4), 5), I want the result equal array(1, B, 2, B, 3, G, 4, B, 5). Since my current function iterates through the array passed to it only once, it will insert A between non-array elements even if an array element is present further down the line. What I'm ultimately trying to do is to flatten a multi-dimensional array, with elements of Glue inserted between the elements of a childless sub-array, and elements of Break inserted between the elements of a parent array. ![]() I guess my example isn't a good enough parallel to my situation, as I have no idea how to implement your solution. foreach 0.0032877922058105 foreach (using reference) 0.0029420852661133 for 0.0025191307067871 foreach (hash table) 0.0035080909729004 for (hash table) 0.0061779022216797 As you can see the evolution is insane, about 560 time faster than reported in 2012. php foreach pass by reference unexpected changes. Getting Invalid argument supplied for foreach as a result of pass by reference variable. This is an exception thrown by almost all of PHP's iterators (there are very few exceptions to this exception) it isn't anything special for SplFixedArray. Alternative to foreach pass by reference. Short answer: don't iterate-by-reference. Strict Standards: Only variables should be passed by reference in going over array. PHP loop through array of object gives unexpected result. php foreach pass by reference unexpected changes. Strange foreach loop after modifying array. ![]() PHP foreach loop odd references behaviour. But foreach doesn't have a built in function to do that as far as I know. PHP foreach statement by reference: unexpected behaviour when reusing iterator. That would work, that way you give it a value and once it hits that it breaks out etc.Īs for which is better, this or a for loop really it is your call.
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